오늘 날짜 반환

| Javascript/jQuery 사용자 함수 2012. 1. 5. 10:46

Posted by venustas

$.extend({

//=====================================================================================

// 오늘 날짜

//=====================================================================================

getToday: function(dateType){

var today = new Date();

switch (dateType){

case 1 :

today = today.getFullYear() + "-" + $.addZero(today.getMonth() + 1) + "-" + $.addZero(today.getDate());

break;

case 2 :

today = today.getFullYear() + $.addZero(today.getMonth() + 1) + $.addZero(today.getDate());

break;

}

return today;

//=====================================================================================

// 10 이하 숫자 앞에 0 삽입

//=====================================================================================

addZero: function(number){

return parseInt(number, 10) < 10 ? "0" + number : number;

}

});

$.getToday(1) : 2012-01-01
$.getToday(2) : 20120101

And

....